Small \( K_c \) means reaction favors reactants at equilibrium.
The reaction in question is: \(\mathrm{N_2(g)} + 3\mathrm{H_2(g)} \leftrightarrow 2\mathrm{NH_3(g)}\). The equilibrium constant \(K_c\) is given as \(4 \times 10^{-3}\) at a certain temperature. To determine which species is favored at equilibrium, we need to analyze the value of \(K_c\).
Step-by-step analysis:
Conclusion:
The correct option is: "Reactants are favored over products". The low \(K_c\) value supports this conclusion as it signifies that, at equilibrium, the concentration of reactants will be higher than that of products.
To determine whether reactants or products are favored at equilibrium, we need to analyze the given equilibrium constant \( K_c \) for the reaction:
\( \mathrm{N_2(g)} + 3\mathrm{H_2(g)} \leftrightarrow 2\mathrm{NH_3(g)} \)
The equilibrium constant \( K_c \) is given as \( 4 \times 10^{-3} \).
Key points to consider:
Since \( K_c = 4 \times 10^{-3} \) is less than 1, this indicates that the equilibrium mixture contains more reactants than products. Therefore, the reaction favors reactants over products at equilibrium.
Correct statement: Reactants are favored over products.
x mg of Mg(OH)$_2$ (molar mass = 58) is required to be dissolved in 1.0 L of water to produce a pH of 10.0 at 298 K. The value of x is ____ mg. (Nearest integer) (Given: Mg(OH)$_2$ is assumed to dissociate completely in H$_2$O)