\(\frac{\Delta \lambda}{\lambda}\) is independent of \(\lambda\)
\(\frac{\Delta \lambda}{\lambda}\) increases with decreasing λ
there is no change in photon's wavelength for all angles of deflection of the photon
\(\frac{\Delta \lambda}{\lambda}\) increases with increasing angle of deflection of the photon
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The Correct Option isB, D
Solution and Explanation
The correct option is (B): \(\frac{\Delta \lambda}{\lambda}\) increases with decreasing λ and (D): \(\frac{\Delta \lambda}{\lambda}\) increases with increasing angle of deflection of the photon