Question:

In the case of an inductor,

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In an inductive circuit, the voltage leads the current by \( \frac{\pi}{2} \) radians due to the nature of inductance, which causes the voltage to react to changes in current.
Updated On: Apr 19, 2025
  • voltage lags the current by \( \frac{\pi}{2} \)
  • voltage leads the current by \( \frac{\pi}{2} \)
  • voltage leads the current by \( \frac{\pi}{3} \)
  • voltage leads the current by \( \frac{\pi}{4} \)
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The Correct Option is B

Solution and Explanation

In an inductive circuit, the voltage \( V \) and the current \( I \) are related through the inductance \( L \) and the frequency of the alternating current. The voltage across an inductor is given by: \[ V_L = L \frac{dI}{dt} \] 
For an AC circuit, the current and voltage can be expressed as: \[ I = I_0 \sin(\omega t) \] \[ V_L = L I_0 \omega \cos(\omega t) \] Since \( \cos(\omega t) = \sin\left(\omega t + \frac{\pi}{2}\right) \), the voltage leads the current by \( \frac{\pi}{2} \) radians in an inductor. 
Thus, the correct answer is: \[ \text{(B) } \text{voltage leads the current by } \frac{\pi}{2} \]

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