Question

In simple harmonic motion, the total mechanical energy of the given system is \( E \). If the mass of the oscillating particle \( P \) is doubled, then the new energy of the system for the same amplitude is:

• A. \( \frac{E}{\sqrt{2}} \)
• B. E
• C. \( E\sqrt{2} \)
• D. \( 2E \)

Answer 1

The Correct Option is B

In a simple harmonic oscillator, the total mechanical energy (T.E.) is given by:
\[ T.E. = \frac{1}{2}kA^2, \] where \( k \) is the spring constant and \( A \) is the amplitude of oscillation.

- Since the amplitude \( A \) remains the same, the total mechanical energy (T.E.) will also remain the same, as it depends only on \( k \) and \( A \), not on the mass \( m \) of the oscillating particle.

Thus, even if the mass of \( P \) is doubled, the total mechanical energy \( E \) will remain unchanged.

Answer: E