In one of the hybridisation experiments, a homozygous dominant parent and a homozygous recessive parent are crossed for a trait. (Plant shows Mendelian inheritance pattern)
The correct answer is: (C) Dominant parent trait appears in both F1 & F2 generations, recessive parent trait appears in only F2 generation.
In a typical Mendelian inheritance pattern, when a homozygous dominant parent (AA) is crossed with a homozygous recessive parent (aa), all the F1 offspring will inherit one dominant allele from the dominant parent and one recessive allele from the recessive parent. Therefore, all F1 individuals will be heterozygous (Aa) and will exhibit the dominant trait.
In the F2 generation, obtained by crossing two F1 individuals (Aa × Aa), the offspring will exhibit a 3:1 phenotypic ratio, where three-fourths of the offspring will show the dominant trait and one-fourth will show the recessive trait. This is because the recessive allele can only express its trait when it is present in a homozygous recessive condition (aa), which only appears in the F2 generation.
Therefore, the dominant parent trait appears in both F1 and F2 generations, while the recessive parent trait appears only in the F2 generation.