Let’s analyze the given information:
Tall (T) is dominant over dwarf (t).
Round (R) is dominant over wrinkled (r).
The parent plant is tall with round seeds. Since some offspring have wrinkled seeds (rr),the parent plant must carry the recessive allele (r). Because all offspring are tall, the parent plant must carry at least one dominant allele (T).
The offspring phenotypes are:
Tall, Round: Could be TTRR, TTRr, TtRR, or TtRr
Tall, Wrinkled: Must be Ttrr
To produce both round and wrinkled seeds, the parent must be heterozygous for seed shape (Rr). Since all offspring are tall, and wrinkled offspring appear, the parent plant must be homozygous dominant for height (TT). If the parent was heterozygous for height (Tt), then some offspring would have been dwarf (tt), which isn’t observed.
Therefore, the parent’s genotype must be TTRr.
Consider a water tank shown in the figure. It has one wall at \(x = L\) and can be taken to be very wide in the z direction. When filled with a liquid of surface tension \(S\) and density \( \rho \), the liquid surface makes angle \( \theta_0 \) (\( \theta_0 < < 1 \)) with the x-axis at \(x = L\). If \(y(x)\) is the height of the surface then the equation for \(y(x)\) is: (take \(g\) as the acceleration due to gravity)
A constant voltage of 50 V is maintained between the points A and B of the circuit shown in the figure. The current through the branch CD of the circuit is :