Step 1: Background.
The lac operon in E. coli regulates lactose metabolism. It has structural genes (Z, Y, A) controlled by a promoter, operator, and regulator gene.
Step 2: Role of Z and Y genes. \[\begin{array}{rl} \bullet & \text{Z gene: Codes for β-galactosidase enzyme.} \\ \bullet & \text{Function: Hydrolyses lactose into glucose and galactose.} \\ \end{array}\] \item Y gene: Codes for Permease enzyme. \[\begin{array}{rl} \bullet & \text{Function: Increases permeability of the cell membrane to allow entry of lactose into the bacterial cell.} \\ \end{array}\] \end{itemize}
Step 3: Conclusion.
Thus, in the lac operon, Z and Y genes play key roles in lactose utilization: Z (breakdown) and Y (transport).
Construct and label a transcription unit from which the RNA segment given below has been transcribed. Write the complete name of the enzyme that transcribed this RNA. 
Student to attempt either option-(A) or (B):
(A) Write the features a molecule should have to act as a genetic material. In the light of the above features, evaluate and justify the suitability of the molecule that is preferred as an ideal genetic material.
OR
(B) Differentiate between the following: