Question:

The RNA triplet UAG acts as a stop codon which terminates the synthesis of a polypeptide. Below is given a strand of DNA which codes for four amino acids.
In which position will an insertion of a thymine nucleotide result in the termination of translation?
DNA strand:
3′ T C C A C C C G A T G C 5′

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Frameshift mutations due to base insertion can create premature stop codons like UAG, ending translation early.
Updated On: Jun 20, 2025
  • 3′ TCCACCCGATGC 5'

  • 3′ TCCACCCGATGC 5′

  • 3′ TCCACCCGATGC 5′

  • 3′ TCCACCCGATGC 5′

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The Correct Option is B

Solution and Explanation

The given DNA strand is 3′ to 5′, and the mRNA will be complementary in 5′ to 3′ direction. Without insertion, the original codons would be:
  • DNA: 3′ TCC ACC CGA TGC 5′
  • mRNA: 5′ AGG UGG GCU ACG 3′ — coding for four amino acids.
Inserting a thymine (T) at position (B) would result in a frameshift mutation. The sequence becomes:
  • DNA: 3′ TCC ACC TCG ATG C 5′
  • mRNA: 5′ AGG UGG AGC UAC G 3′ — which includes the stop codon UAG, terminating translation prematurely.
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