In general, the properties that decrease and increase down a group in the periodic table respectively are:
Electronegativity is the tendency of an atom to attract a shared pair of electrons towards itself. It decreases as we go down the group.
Electronegativity decreases and atomic radius increases as we go down the group.
Hence, option B) electronegativity and atomic radius is the correct answer.
The summary of the variation of periodic properties is given in the table as shown below.
Thus, electronegativity decreases and atomic radius increases down a group in the periodic table.
Therefore, In general, the properties that decrease and increase down a group in the periodic table respectively are electronegativity and atomic radius.
Electronegativity is the tendency of an atom to attract a shared pair of electrons towards itself. It decreases as we go down the group.
Atomic radius is the distance between the nucleus of an atom to its outer electron shell.
Therefore, Option (B) is correct.
As one moves down a group (vertical column) in the periodic table, the atomic number increases, resulting in an increase in the size of the atom (atomic radius). On the other hand, electronegativity decreases down a group
Let \( \alpha, \beta \) be the roots of the equation \( x^2 - ax - b = 0 \) with \( \text{Im}(\alpha) < \text{Im}(\beta) \). Let \( P_n = \alpha^n - \beta^n \). If \[ P_3 = -5\sqrt{7}, \quad P_4 = -3\sqrt{7}, \quad P_5 = 11\sqrt{7}, \quad P_6 = 45\sqrt{7}, \] then \( |\alpha^4 + \beta^4| \) is equal to:
For the thermal decomposition of \( N_2O_5(g) \) at constant volume, the following table can be formed, for the reaction mentioned below: \[ 2 N_2O_5(g) \rightarrow 2 N_2O_4(g) + O_2(g) \] Given: Rate constant for the reaction is \( 4.606 \times 10^{-2} \text{ s}^{-1} \).
O\(_2\) gas will be evolved as a product of electrolysis of:
(A) an aqueous solution of AgNO3 using silver electrodes.
(B) an aqueous solution of AgNO3 using platinum electrodes.
(C) a dilute solution of H2SO4 using platinum electrodes.
(D) a high concentration solution of H2SO4 using platinum electrodes.
Choose the correct answer from the options given below :
Classification of Haloalkanes and Haloarenes are as follows:
Haloalkanes and Haloarenes are Classified on the Basis of the Number of Halogen Atoms:
These are further classified as mono, di, or polyhalogen (tri-,tetra-, etc.) compounds depending on whether they contain one, two or more halogen atoms in their structures. For example;
Haloalkanes and Haloarenes are Classified on Compounds Containing sp3 C—X Bond (X= F, Cl, Br, I)
This class includes:
Haloalkanes and Haloarenes are Classified on Compounds Containing sp2 C—X Bond
This class includes: