Question:
In Freundlich adsorption isotherm, slope of AB line is :
In Freundlich adsorption isotherm, slope of AB line is :
Updated On: Apr 28, 2025
- $\log n$ with $( n >1)$
- $n$ with $( n , 0.1$ to 0.5$)$
- $\log \frac{1}{n}$ with $(n<1)$
- $\frac{1}{ n }$ with $\left(\frac{1}{ n }=0\right.$ to $\left.1\right)$
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The Correct Option is D
Solution and Explanation
$\frac{x}{m}=K(P)^{1 / n}$
$\log \left(\frac{ x }{ m }\right)=\log K +\frac{1}{ n } \log P$
$y = c + mx$
$m =1 / n$ so slope will be equal to $1 / n$
$\log \left(\frac{ x }{ m }\right)=\log K +\frac{1}{ n } \log P$
$y = c + mx$
$m =1 / n$ so slope will be equal to $1 / n$
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Concepts Used:
Adsorption
Heinrich Kayser, the German physicist was the first to coin the term adsorption. Adsorption can be explained as a surface phenomenon where particles remain attached on the top of a material. Generally, it comprises the molecules, atoms, liquid, solid in a dissolved stage, even the ions of a gas that are attached to the surface. Much to our surprise, the consequence of surface energy i.e. adsorption is present in biological, physical, chemical, and natural systems and are used in many industrial applications.
