Question:
In $Cu$-ammonia complex, the state of hybridization of $Cu^{+2}$ is
In $Cu$-ammonia complex, the state of hybridization of $Cu^{+2}$ is
Updated On: Jun 18, 2022
- $sp^{3}$
- $d^{3}s$
- $sp^{2}f$
- $dsp^{2}$
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The Correct Option is D
Solution and Explanation
$Cu$-ammonia complex is $\left[ Cu \left( NH _{3}\right)_{4}\right]^{2+}$
$NH_3$, being strong field ligand, shifts the unpaired electron to higher level.
$NH_3$, being strong field ligand, shifts the unpaired electron to higher level.
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Concepts Used:
Coordination Compounds
A coordination compound holds a central metal atom or ion surrounded by various oppositely charged ions or neutral molecules. These molecules or ions are re-bonded to the metal atom or ion by a coordinate bond.
Coordination entity:
A coordination entity composes of a central metal atom or ion bonded to a fixed number of ions or molecules.
Ligands:
A molecule, ion, or group which is bonded to the metal atom or ion in a complex or coordination compound by a coordinate bond is commonly called a ligand. It may be either neutral, positively, or negatively charged.