
Phosphate ester linkage is the covalent bond that will connect the sugar molecules with the backbone. This linkage occurs between 3’ carbon of one sugar to the 5’ carbon of the adjacent carbon. The phosphate will provide a negative charge and maintain the stability.
On the other hand, the heterocyclic base is attached to the Carbon-1’ of both DNA and RNA sugar molecules. The bases present in them are adenine, guanine, cytosine, uracil and thymine.
Given below are two statements:
Statement I: D-(+)-glucose + D-(+)-fructose $\xrightarrow{H_2O}$ sucrose sucrose $\xrightarrow{\text{Hydrolysis}}$ D-(+)-glucose + D-(+)-fructose
Statement II: Invert sugar is formed during sucrose hydrolysis.
In the light of the above statements, choose the correct answer from the options given below -
In the given figure, the blocks $A$, $B$ and $C$ weigh $4\,\text{kg}$, $6\,\text{kg}$ and $8\,\text{kg}$ respectively. The coefficient of sliding friction between any two surfaces is $0.5$. The force $\vec{F}$ required to slide the block $C$ with constant speed is ___ N.
(Given: $g = 10\,\text{m s}^{-2}$) 
Method used for separation of mixture of products (B and C) obtained in the following reaction is: 