\( X_5Y_3 \)
In a bcc lattice with X atoms at the corners and Y atoms at the center, each corner atom contributes \(\frac{1}{8}\) of an atom to the unit cell and the center atom contributes entirely. Normally, there would be 1 Y atom and \(8 \times \frac{1}{8} = 1\) X atom per unit cell. However, with three X atoms missing, \(1 - 3 \times \frac{1}{8} = \frac{5}{8}\) contributions from X atoms remain. Thus, the formula becomes approximately \( X_{5}Y_{8} \).
Arrange the above carbocations in the order of decreasing stability:
Consider the following reaction sequence. What are A and B?
What is the value of 'n' in 'Z' of the following sequence?
What is 'Z' in the given sequence of reactions?
Match the following reactions with their corresponding products:
A constant force of \[ \mathbf{F} = (8\hat{i} - 2\hat{j} + 6\hat{k}) \text{ N} \] acts on a body of mass 2 kg, displacing it from \[ \mathbf{r_1} = (2\hat{i} + 3\hat{j} - 4\hat{k}) \text{ m to } \mathbf{r_2} = (4\hat{i} - 3\hat{j} + 6\hat{k}) \text{ m}. \] The work done in the process is:
A ball 'A' of mass 1.2 kg moving with a velocity of 8.4 m/s makes a one-dimensional elastic collision with a ball 'B' of mass 3.6 kg at rest. The percentage of kinetic energy transferred by ball 'A' to ball 'B' is:
A metre scale is balanced on a knife edge at its centre. When two coins, each of mass 9 g, are kept one above the other at the 10 cm mark, the scale is found to be balanced at 35 cm. The mass of the metre scale is:
A body of mass \( m \) and radius \( r \) rolling horizontally with velocity \( V \), rolls up an inclined plane to a vertical height \( \frac{V^2}{g} \). The body is: