Step 1: Determine translation speed.
300 amino acids are synthesized in 20 s.
Thus, ribosome speed = \[ \frac{300\ \text{aa}}{20\ \text{s}} = 15\ \text{aa/s} \] Step 2: Estimate protein length from nucleotide count.
1350 nucleotides = \[ \frac{1350}{3} = 450\ \text{codons (amino acids)} \] Step 3: Time required to translate one protein.
\[ t = \frac{450\ \text{aa}}{15\ \text{aa/s}} = 30\ \text{s} \] Step 4: mRNA lifetime.
mRNA lifetime = 2 minutes = 120 seconds.
Step 5: Number of ribosomes translating simultaneously.
In bacteria, ribosomes initiate one after another during translation. Number of ribosomes = \[ \frac{120\ \text{s}}{30\ \text{s}} = 4 \] Step 6: Consider ribosome spacing.
Length of coding region = 1350 nt. One ribosome occupies ~75 nt. Maximum packing: \[ \frac{1350}{75} = 18\ \text{ribosomes} \] Step 7: Conclusion.
Thus, a maximum of 18 ribosomes can translate the mRNA.
Identify the taxa that constitute a paraphyletic group in the given phylogenetic tree.
The vector, shown in the figure, has promoter and RBS sequences in the 300 bp region between the restriction sites for enzymes X and Y. There are no other sites for X and Y in the vector. The promoter is directed towards the Y site. The insert containing only an ORF provides 3 fragments after digestion with both enzymes X and Y. The ORF is cloned in the correct orientation in the vector using the single restriction enzyme Y. The size of the largest fragment of the recombinant plasmid expressing the ORF upon digestion with enzyme X is ........... bp. (answer in integer) 