The resonance frequency \( f_0 \) of an LCR circuit is given by:
\( f_0 = \frac{1}{2 \pi} \sqrt{\frac{1}{LC}} \).
As the capacitance \( C \) increases, the resonance frequency \( f_0 \) decreases, because \( f_0 \) is inversely proportional to the square root of \( C \). This means that as \( C \) increases, \( f_0 \) decreases, resulting in a graph with a downward slope as \( C \) increases.
Find output voltage in the given circuit.
A | B | Y |
0 | 0 | 1 |
0 | 1 | 0 |
1 | 0 | 1 |
1 | 1 | 0 |
You are given a dipole of charge \( +q \) and \( -q \) separated by a distance \( 2l \). A sphere 'A' of radius \( R \) passes through the centre of the dipole as shown below and another sphere 'B' of radius \( 2R \) passes through the charge \( +q \). Then the electric flux through the sphere A is