In an LCR series circuit, the value of only capacitance \( C \) is varied. The resulting variation of resonance frequency \( f_0 \) as a function of \( C \) can be represented as
The Correct Option is C
Solution and Explanation
The resonance frequency \( f_0 \) of an LCR circuit is given by:
\( f_0 = \frac{1}{2 \pi} \sqrt{\frac{1}{LC}} \).
As the capacitance \( C \) increases, the resonance frequency \( f_0 \) decreases, because \( f_0 \) is inversely proportional to the square root of \( C \). This means that as \( C \) increases, \( f_0 \) decreases, resulting in a graph with a downward slope as \( C \) increases.
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