Step 1: Use the formula for the frequency of oscillation in an LC circuit
The frequency \( f \) of an LC circuit is given by the formula:
\[
f = \frac{1}{2\pi \sqrt{LC}}
\]
where:
- \( L \) is the inductance,
- \( C \) is the capacitance,
- \( f \) is the frequency of oscillation.
Step 2: Substitute the given values
Given:
- Inductance \( L = 2 \, \text{H} \),
- Capacitance \( C = 4 \, \mu\text{F} = 4 \times 10^{-6} \, \text{F} \).
Now, substitute these values into the formula:
\[
f = \frac{1}{2\pi \sqrt{2 \times 4 \times 10^{-6}}}
\]
\[
f = \frac{1}{2\pi \sqrt{8 \times 10^{-6}}}
\]
\[
f = \frac{1}{2\pi \times 2.83 \times 10^{-3}} = \frac{1}{1.78 \times 10^{-2}} = 56.3 \, \text{Hz}
\]
Answer: Therefore, the frequency of oscillation of the LC circuit is approximately \( 50 \, \text{Hz} \). So, the correct answer is option (2).