Question

An ammeter connected in series in an AC circuit reads \( 10 \, \text{A} \). The maximum value of current at any instant in the circuit is:

• A. \( 10\sqrt{2} \, \text{A} \)
• B. \( \dfrac{10}{\sqrt{2}} \, \text{A} \)
• C. \( \dfrac{10}{\pi} \, \text{A} \)
• D. \( \dfrac{10}{\sqrt{2}\pi} \, \text{A} \)

Hint:

In AC circuits, the reading of an ammeter is the RMS value. To find the peak current, multiply the RMS value by \( \sqrt{2} \).

Answer 1

The Correct Option is A

An ammeter in an AC circuit measures the rms (root mean square) value of current, not the peak value. The relationship between the peak current \( I_0 \) and the rms current \( I_{\text{rms}} \) is: \[ I_0 = I_{\text{rms}} \cdot \sqrt{2} \] Given: \[ I_{\text{rms}} = 10 \, \text{A} \Rightarrow I_0 = 10 \cdot \sqrt{2} \, \text{A} \] Final answer: \( 10\sqrt{2} \, \text{A} \)