To understand the expression \(a \times 10^b\), we need to determine what the "order of magnitude" refers to, especially in the context of scientific notation.
In scientific notation, any number can be expressed as \(a \times 10^b\), where:
The order of magnitude refers specifically to the power of 10 that best fits the scale of the number. In other words, it is the exponent \(b\) in the expression.
Exploring the given options:
Hence, the correct answer is: \(b\) is the order of magnitude for \(a \leq 5\).
This conclusion holds because regardless of \(a\)'s specific value within its allowed range, it is the exponent \(b\) in \(10^b\) that dictates the order of magnitude of the expression.
The expression \(a \times 10^b\) is in scientific notation, where:
\[ 1 \leq a < 10, \quad \text{and } b \text{ is an integer}. \]
The order of magnitude of a number is the power of 10 closest to that number. The value of \(a\) determines how the exponent \(b\) is interpreted:
Case 1: \(a \leq 5\) When \(a\) is less than or equal to 5, the number is closer to \(10^b\) than \(10^{b+1}\).
Therefore, the order of magnitude is:
\[ \text{Order of magnitude} = b. \]
Case 2: \(a > 5\) When \(a\) is greater than 5, the number is closer to \(10^{b+1}\) than \(10^b\). In this case, the order of magnitude becomes:
\[ \text{Order of magnitude} = b + 1. \]
The problem specifies \(a \leq 5\), so the order of magnitude directly matches the exponent \(b\).
Which one of the following graphs accurately represents the plot of partial pressure of CS₂ vs its mole fraction in a mixture of acetone and CS₂ at constant temperature?

In the given figure, the blocks $A$, $B$ and $C$ weigh $4\,\text{kg}$, $6\,\text{kg}$ and $8\,\text{kg}$ respectively. The coefficient of sliding friction between any two surfaces is $0.5$. The force $\vec{F}$ required to slide the block $C$ with constant speed is ___ N.
(Given: $g = 10\,\text{m s}^{-2}$) 