The expression \(a \times 10^b\) is in scientific notation, where:
\[ 1 \leq a < 10, \quad \text{and } b \text{ is an integer}. \]
The order of magnitude of a number is the power of 10 closest to that number. The value of \(a\) determines how the exponent \(b\) is interpreted:
Case 1: \(a \leq 5\) When \(a\) is less than or equal to 5, the number is closer to \(10^b\) than \(10^{b+1}\).
Therefore, the order of magnitude is:
\[ \text{Order of magnitude} = b. \]
Case 2: \(a > 5\) When \(a\) is greater than 5, the number is closer to \(10^{b+1}\) than \(10^b\). In this case, the order of magnitude becomes:
\[ \text{Order of magnitude} = b + 1. \]
The problem specifies \(a \leq 5\), so the order of magnitude directly matches the exponent \(b\).
If \[ \frac{dy}{dx} + 2y \sec^2 x = 2 \sec^2 x + 3 \tan x \cdot \sec^2 x \] and
and \( f(0) = \frac{5}{4} \), then the value of \[ 12 \left( y \left( \frac{\pi}{4} \right) - \frac{1}{e^2} \right) \] equals to: