We are told:
\[ P = 0.45N \]
The score is 68% less than the pass mark: \[ 36 = P - 0.68P = 0.32P \]
\[ P = \frac{36}{0.32} = 112.5 \]
Since \( P = 0.45N \): \[ 0.45N = 112.5 \] \[ N = \frac{112.5}{0.45} = 250 \]
\[ 243 \le 250 \le 252 \] This is true.
✅ Final Answer: \( \mathbf{243 \le N \le 252} \)