Question:
In an examination, Rama's score was one-twelfth of the sum of the scores of Mohan and Anjali. After a review, the score of each of them increased by 6. The revised scores of Anjali, Mohan, and Rama were in the ratio 11:10:3. Then Anjali's score exceeded Rama's score by
In an examination, Rama's score was one-twelfth of the sum of the scores of Mohan and Anjali. After a review, the score of each of them increased by 6. The revised scores of Anjali, Mohan, and Rama were in the ratio 11:10:3. Then Anjali's score exceeded Rama's score by
Updated On: Sep 17, 2024
- 24
- 26
- 32
- 35
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The Correct Option is C
Solution and Explanation
Their post-review scores are 11x, 10x, and 3x, respectively.
Consequently, their scores prior to the review can be expressed as \((11x - 6), (10x - 6),\) and \((3x - 6), \)respectively.
It is specified that Rama's score equaled one-twelfth of the sum of Mohan and Anjali's scores.
\(⇒ (3x-6)=\frac{1}{12}[(11x-6)+(10x-6)]\)
\(⇒ 12(3x-6)=21x-12\)
\(⇒ 36x-72=21x-12\)
\(⇒ 36x-21x=72-12=60\)
\(⇒ x=4\)
Now, Anjali’s score – Rama’s score \(= (11x-6)-(3x-6)=8x =32.\)
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