Question:

In an examination, 62% of the candidates failed in English, 42% in Mathematics and 20% in both. The number of those who passed in both the subjects is: 
 

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Use the principle of inclusion-exclusion to find the percentage of candidates who failed in either English or Mathematics or both.
Updated On: Mar 26, 2025
  • 11
  • 16
  • 18
  • None of these
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The Correct Option is B

Solution and Explanation

Step 1: Calculate the percentage of candidates who failed in either English or Mathematics or both
Percentage failed in English or Mathematics or both = Percentage failed in English + Percentage failed in Mathematics - Percentage failed in both = 62% + 42% - 20% = 84% 
Step 2: Calculate the percentage of candidates who passed in both subjects
Percentage passed in both subjects = 100% - Percentage failed in English or Mathematics or both = 100% - 84% = 16% 
Step 3: Assume the total number of candidates
Let the total number of candidates be \( x \). 
Step 4: Calculate the number of candidates who passed in both subjects
Number of candidates who passed in both subjects = 16% of \( x \) = \( \frac{16}{100} \times x \) 
Step 5: Relate the number to the options
Since the options are whole numbers, we can assume \( x = 100 \) for simplicity. Then, the number of candidates who passed in both subjects = \( \frac{16}{100} \times 100 = 16 \).
 

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