Resistance (R) = $\frac{V}{I} = \frac{200}{20} = 10 \, \Omega$
$\frac{\Delta R}{R} = \frac{\Delta V}{V} + \frac{\Delta I}{I}$
$\frac{\Delta R}{10} = \frac{4}{200} + \frac{0.2}{20} = 0.02 + 0.01 = 0.03$
$\Delta R = 0.3 \, \Omega$
Thus, R = (10 ± 0.3) Ω
Two cells of emf 1V and 2V and internal resistance 2 \( \Omega \) and 1 \( \Omega \), respectively, are connected in series with an external resistance of 6 \( \Omega \). The total current in the circuit is \( I_1 \). Now the same two cells in parallel configuration are connected to the same external resistance. In this case, the total current drawn is \( I_2 \). The value of \( \left( \frac{I_1}{I_2} \right) \) is \( \frac{x}{3} \). The value of x is 1cm.
In the figure shown below, a resistance of 150.4 $ \Omega $ is connected in series to an ammeter A of resistance 240 $ \Omega $. A shunt resistance of 10 $ \Omega $ is connected in parallel with the ammeter. The reading of the ammeter is ______ mA.
The output (Y) of the given logic implementation is similar to the output of an/a …………. gate.