Resistance (R) = $\frac{V}{I} = \frac{200}{20} = 10 \, \Omega$
$\frac{\Delta R}{R} = \frac{\Delta V}{V} + \frac{\Delta I}{I}$
$\frac{\Delta R}{10} = \frac{4}{200} + \frac{0.2}{20} = 0.02 + 0.01 = 0.03$
$\Delta R = 0.3 \, \Omega$
Thus, R = (10 ± 0.3) Ω
The current passing through the battery in the given circuit, is:
AB is a part of an electrical circuit (see figure). The potential difference \(V_A - V_B\), at the instant when current \(i = 2\) A and is increasing at a rate of 1 amp/second is: