Understanding the Phase Relationship in AC Circuits:
In an AC circuit: For a pure inductor, the current \( I \) lags the voltage \( V \) by \( 90^\circ \) (or \(\(\frac{\pi}{2}\) \) radians).
For a pure capacitor, the current \( I \) leads the voltage \( V \) by \( 90^\circ \). For a pure resistor, the current and voltage are in phase, meaning that they reach zero and maximum values simultaneously.
Condition for Instantaneous Current to be Zero When Voltage is Maximum:
The given condition (current is zero when voltage is maximum) implies a \( 90^\circ \) phase difference between the current and voltage.
This situation occurs in:
- A pure inductor, where current lags the voltage by \( 90^\circ \).
- A pure capacitor, where current leads the voltage by \( 90^\circ \).
- A combination of an inductor and capacitor (LC circuit), where the phase difference can also result in current being zero when voltage is maximum.
Conclusion:
Since this phase relationship is possible in a pure inductor, pure capacitor, or an LC combination, the correct answer is Option (4): A, B, and D only.
Draw the plots showing the variation of magnetic flux φ linked with the loop with time t and variation of induced emf E with time t. Mark the relevant values of E, φ and t on the graphs.
Let a line passing through the point $ (4,1,0) $ intersect the line $ L_1: \frac{x - 1}{2} = \frac{y - 2}{3} = \frac{z - 3}{4} $ at the point $ A(\alpha, \beta, \gamma) $ and the line $ L_2: x - 6 = y = -z + 4 $ at the point $ B(a, b, c) $. Then $ \begin{vmatrix} 1 & 0 & 1 \\ \alpha & \beta & \gamma \\ a & b & c \end{vmatrix} \text{ is equal to} $
20 mL of sodium iodide solution gave 4.74 g silver iodide when treated with excess of silver nitrate solution. The molarity of the sodium iodide solution is _____ M. (Nearest Integer value) (Given : Na = 23, I = 127, Ag = 108, N = 14, O = 16 g mol$^{-1}$)