In a Young' double slit experiment. if there is no initial phase difference between the light from the two slits, a point on the screen corresponding to the fifth minimum has path difference.
Path difference for \(n^{th}\) minima \(=(2n - 1) \frac{\lambda}{2}\) For fifth minima \((n = 5) = \frac{9\lambda}{2}\) Therefore, the correct option is (C) : \(9\frac{\lambda}{2}\)