Question:

In a Young' double slit experiment. if there is no initial phase difference between the light from the two slits, a point on the screen corresponding to the fifth minimum has path difference.

Updated On: May 17, 2024
  • $5\frac{\lambda}{2}$
  • $10\frac{\lambda}{2}$
  • $9\frac{\lambda}{2}$
  • $11\frac{\lambda}{2}$
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The Correct Option is C

Solution and Explanation

Path difference for \(n^{th}\) minima \(=(2n - 1) \frac{\lambda}{2}\) 
For fifth minima \((n = 5) = \frac{9\lambda}{2}\)
Therefore, the correct option is (C) : \(9\frac{\lambda}{2}\)

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