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in a triangle abc r 1 cot dfrac a 2 r 2 cot dfrac
Question:
In a triangle ABC,
$r_1 \cot \dfrac{A}{2} + r_2 \cot \dfrac{B}{2} + r_3 \cot \dfrac{C}{2} = $ ?
Show Hint
Each $r_i \cot\left(\dfrac{\text{angle}}{2}\right) = s$ in a triangle; so the sum over all three equals $3s$.
AP EAPCET - 2022
AP EAPCET
Updated On:
May 18, 2025
$s$
$2s$
$3s$
$\dfrac{s}{2}$
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The Correct Option is
C
Solution and Explanation
Using the identity: \[ r_a \cot\left(\frac{A}{2}\right) = s,\quad r_b \cot\left(\frac{B}{2}\right) = s,\quad r_c \cot\left(\frac{C}{2}\right) = s \Rightarrow r_1 \cot \frac{A}{2} + r_2 \cot \frac{B}{2} + r_3 \cot \frac{C}{2} = s + s + s = 3s \]
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