Step 1: The focal length \( f \) of a spherical mirror is the distance between the pole and the focal point.
Step 2: Given that the distance between the focus and centre of curvature is \( 20 \, \text{cm} \), we know that: \[ f = 20 \, \text{cm} \] \[ \boxed{20 \, \text{cm} \text{ (Focal length)}} \]
(ii) The distance of pole of mirror from its centre of curvature
Solution:
Step 1: The radius of curvature \( R \) is the distance between the pole and the centre of curvature.
Step 2: Since the focal length is given as \( f = 20 \, \text{cm} \), we use the relation: \[ R = 2f \]
Step 3: Substituting the given value: \[ R = 2 \times 20 = 40 \, \text{cm} \] \[ \boxed{40 \, \text{cm} \text{ (Radius of curvature)}} \]
(b) Order of the differential equation: $ 5x^3 \frac{d^3y}{dx^3} - 3\left(\frac{dy}{dx}\right)^2 + \left(\frac{d^2y}{dx^2}\right)^4 + y = 0 $