Question

In a simple RC high-pass filter, the desired roll-off frequency is 15 Hz and \(C = 10\ \mu F\). The value of \(R\) would be _______.

• A. 1.06 KHz
• B. 13.33 KHz
• C. 6.67 KHz
• D. 5 KHz

Hint:

Use \(f_c = \frac{1}{2\pi RC}\) for cutoff frequency in RC filters. Always convert \(\mu F\) to Farads.

Answer 1

The Correct Option is A

Step 1: Use cutoff frequency formula: \[ f_c = \frac{1}{2\pi RC} \] Given: \[ f_c = 15\ \text{Hz},\ C = 10\ \mu F = 10 \times 10^{-6} \] Step 2: Rearranging: \[ R = \frac{1}{2\pi f_c C} = \frac{1}{2\pi \cdot 15 \cdot 10 \times 10^{-6}} = \frac{1}{0.000942} \approx 1061\ \Omega \approx 1.06\ \text{K}\Omega \]