To determine the genotype of a black seed plant, a test cross can be conducted. The black seed phenotype can be either homozygous dominant (BB) or heterozygous (Bb). To differentiate between these possibilities, cross the black seed plant with a homozygous recessive plant (bb), which has white seeds. Here’s the reasoning:
In conclusion, crossing the black seed plant with a homozygous recessive (bb) plant will elucidate the genotype of the black seed plant based on the phenotypes of the progeny. This approach is known as a test cross. Therefore, the correct cross is with bb.
Three identical heat conducting rods are connected in series as shown in the figure. The rods on the sides have thermal conductivity 2K while that in the middle has thermal conductivity K. The left end of the combination is maintained at temperature 3T and the right end at T. The rods are thermally insulated from outside. In steady state, temperature at the left junction is \(T_1\) and that at the right junction is \(T_2\). The ratio \(T_1 / T_2\) is