In a new temperature scale say $ ^oP $, the boiling and freezing points of water at one atmosphere are $ 100^o P $ and $ 300^o P $ respectively. Correlate this scale with the Centigrade scale. The reading of $ 0^o P $ on the Centigrade scale is:

Question

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Step 1: Establishing the correlation formula. - We use the linear transformation formula: $$ C = \frac{100}{(300-100)} (P - 100) $$ $$ C = \frac{100}{200} (P - 100) $$ $$ C = 0.5 (P - 100) $$ Step 2: Calculating for $ 0^o P $. $$ C = 0.5 (0 - 100) = -50^o C $$ Step 3: Selecting the correct option. Since $ 0^o P $ corresponds to $ -50^o C $, the correct answer is (D).

Answer

Answer

Answer

$ 100^o C $

Answer

$ 150^o C $

In a new temperature scale say \( ^oP \), the boiling and freezing points of water at one atmosphere are \( 100^o P \) and \( 300^o P \) respectively. Correlate this scale with the Centigrade scale. The reading of \( 0^o P \) on the Centigrade scale is:

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The Correct Option is D

Solution and Explanation

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