Question:
In a hydraulic lift, the surface area of the input piston is 6 cm² and that of the output piston is 1500 cm². If 100 N force is applied to the input piston to raise the output piston by 20 cm, then the work done is kJ.
In a hydraulic lift, the surface area of the input piston is 6 cm² and that of the output piston is 1500 cm². If 100 N force is applied to the input piston to raise the output piston by 20 cm, then the work done is kJ.
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In hydraulic systems, work done can be calculated using the force applied and the displacement of the output piston.
Updated On: Mar 24, 2025
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Correct Answer: 0.01
Solution and Explanation
Using the work-energy principle, the work done is calculated as the force applied multiplied by the displacement. The displacement of the output piston is 20 cm, and the force is 100 N. The work is then converted to kJ.
Thus, the correct answer is 0.01 kJ.
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