This is a test cross, where an organism heterozygous for two traits (AaBb) is crossed with one that is homozygous recessive for both traits (aabb).
Parent 1 genotype: AaBb
Parent 2 genotype: aabb
Gametes from AaBb:
Since AaBb is heterozygous for both traits, it can produce 4 types of gametes:
\[
\text{AB},\ \text{Ab},\ \text{aB},\ \text{ab}
\]
Gametes from aabb:
Since aabb is homozygous recessive, it can produce only 1 type of gamete:
\[
\text{ab}
\]
F\textsubscript{1 Generation Offspring:}
Crossing the above gametes gives 4 possible combinations:
\begin{tabular}{ll}
AB × ab & $\rightarrow$ AaBb
Ab × ab & $\rightarrow$ Aabb
aB × ab & $\rightarrow$ aaBb
ab × ab & $\rightarrow$ aabb
\end{tabular}
Each genotype corresponds to a unique phenotype:
AaBb: dominant for both traits
Aabb: dominant for first, recessive for second
aaBb: recessive for first, dominant for second
aabb: recessive for both traits
Thus, the phenotypic ratio =
\[
\boxed{1 : 1 : 1 : 1}
\]