Question:
In a circle of radius 11 cm, CD is a diameter and AB is a chord of length 20.5 cm. If AB and CD intersect at a point E inside the circle and CE has length 7 cm, then the difference of the lengths of BE and AE, in cm, is
In a circle of radius 11 cm, CD is a diameter and AB is a chord of length 20.5 cm. If AB and CD intersect at a point E inside the circle and CE has length 7 cm, then the difference of the lengths of BE and AE, in cm, is
Updated On: Oct 10, 2024
- 2.5
- 3.5
- 0.5
- 1.5
Hide Solution
Verified By Collegedunia
The Correct Option is C
Solution and Explanation
Referring to the diagram below:
Using the chord-chord power theorem, the product of AE and BE is equal to the product of CE and DE, given by AE x BE = 7 x 15 = 105 …(1)
Additionally, it is provided that AE + BE = 20.5 ...(2)
Applying the formula (AE - BE)2 = (AE + BE)2 - 4 x AE x BE, we find (AE - BE)2 = (20.5)2 - 4 x 105, leading to (AE - BE)2 = 420.25 - 420 = 0.25
Consequently, (AE - BE) equals 0.5
Using the chord-chord power theorem, the product of AE and BE is equal to the product of CE and DE, given by AE x BE = 7 x 15 = 105 …(1)
Additionally, it is provided that AE + BE = 20.5 ...(2)
Applying the formula (AE - BE)2 = (AE + BE)2 - 4 x AE x BE, we find (AE - BE)2 = (20.5)2 - 4 x 105, leading to (AE - BE)2 = 420.25 - 420 = 0.25
Consequently, (AE - BE) equals 0.5
Was this answer helpful?
0
0
Top Questions on Triangles, Circles & Quadrilaterals
- A rectangle with the largest possible area is drawn inside a semicircle of radius 2 cm. Then, the ratio of the lengths of the largest to the smallest side of this rectangle is
- CAT - 2023
- Quantitative Aptitude
- Triangles, Circles & Quadrilaterals
- Let \(ΔABC\) be an isosceles triangle such that \(AB\) and \(AC\) are of equal length. \(AD\) is the altitude from \(A\) on \(BC\) and \(BE\) is the altitude from \(B\) on \(AC\) . If \(AD\) and \(BE\) intersect at \(O\) such that \(∠AOB =105\degree\) , then \(\frac{AD}{BE}\) equals
- CAT - 2023
- Quantitative Aptitude
- Triangles, Circles & Quadrilaterals
ABCD is a trapezoid where BC is parallel to AD and perpendicular to AB . Kindly note that BC<AD . P is a point on AD such that CPD is an equilateral triangle. Q is a point on BC such that AQ is parallel to PC . If the area of the triangle CPD is 4√3. Find the area of the triangle ABQ.
- XAT - 2023
- Quantitative Ability and Data Interpretation
- Triangles, Circles & Quadrilaterals
- The problem below consists of a question and two statements numbered 1 & 2. You have to decide whether the data provided in the statements are sufficient to answer the question.
In a cricket match, three slip fielders are positioned in a straight line. The distance between the 1st slip and the 2nd slip is the same as the distance between the 2nd slip and the 3rd slip. The player X, who is not on the same line of slip fielders, throws a ball to the 3rd slip and the ball takes 5 seconds to reach the player at the 3rd slip. If he had thrown the ball at the same speed to the 1st slip or to the 2nd slip, it would have taken 3 seconds or 4 seconds, respectively. What is the distance between the 2nd slip and player X?
1. The ball travels at a speed of 3.6 km/hour.
2. The distance between the 1st slip and the 3rd slip is 2 meters.- XAT - 2023
- Quantitative Ability and Data Interpretation
- Triangles, Circles & Quadrilaterals
- ABC is a triangle and the coordinates of A, B, and C are (a, b - 2c), (a, b + 4c), and (-2a, 3c), respectively, where a, b, and c are positive numbers. The area of the triangle ABC is:
- XAT - 2023
- Quantitative Ability and Data Interpretation
- Triangles, Circles & Quadrilaterals
View More Questions
Questions Asked in CAT exam
- The sum of all real values of $k$ for which $(\frac{1}{8})^k \times (\frac{1}{32768})^{\frac{4}{3}} = \frac{1}{8} \times (\frac{1}{32768})^{\frac{k}{3}}$ is
- CAT - 2024
- Logarithms
- Amal and Vimal together can complete a task in 150 days, while Vimal and Sunil together can complete the same task in 100 days. Amal starts working on the task and works for 75 days, then Vimal takes over and works for 135 days. Finally, Sunil takes over and completes the remaining task in 45 days. If Amal had started the task alone and worked on all days, Vimal had worked on every second day, and Sunil had worked on every third day, then the number of days required to complete the task would have been
- CAT - 2024
- Time and Work
- Gopi marks a price on a product in order to make 20% profit. Ravi gets 10% discount on this marked price, and thus saves Rs 15. Then, the profit, in rupees, made by Gopi by selling the product to Ravi, is
- CAT - 2024
- Profit and Loss
- Sam can complete a job in 20 days when working alone. Mohit is twice as fast as Sam and thrice as fast as Ayana in the same job. They undertake a job with an arrangement where Sam and Mohit work together on the first day, Sam and Ayana on the second day, Mohit and Ayana on the third day, and this three-day pattern is repeated till the work gets completed. Then, the fraction of total work done by Sam is
- CAT - 2024
- Time and Work
- The number of all positive integers up to 500 with non-repeating digits is
- CAT - 2024
- Number Systems
View More Questions