To determine how long A takes to run 200 meters, we start by analyzing the given race scenarios:
When A gives B a start of 20 meters in a 100-meter race, A wins by 5 seconds. This means when A finishes 100 meters, B covers 80 meters and takes an additional 5 seconds to complete the remaining 20 meters.
In another scenario, when A gives B a start of 40 meters, the race ends in a dead heat. This means A and B finish the 100 meters simultaneously, with B having already covered 40 meters upfront.
From these conditions, we derive the following equations:
First Scenario:
Let the speeds of A and B be \( v_A \) and \( v_B \) meters per second respectively. A covers 100 meters in \( \frac{100}{v_A} \) seconds.
Since B covers 80 meters in \( \frac{80}{v_B} \) seconds and takes an additional 5 seconds for the next 20 meters, \( \frac{100}{v_A} = \frac{80}{v_B} + 5 \).
Second Scenario:
For a dead heat, the time for A and B to cover their respective distances (both reaching 100 meters) is equal:
\(\frac{100}{v_A} = \frac{60}{v_B}\).
We now solve these equations to find \( v_A \):
From the second scenario, express \( v_B \):
\( v_B = \frac{60 \cdot v_A}{100}\) or \( v_B = 0.6v_A \).
Substitute \( v_B \) in the first scenario:
\(\frac{100}{v_A} = \frac{80}{0.6v_A} + 5\).
Solving results in:
\(\frac{100}{v_A} = \frac{80 \times 1.67}{v_A} + 5\).
Rearranging terms gives us:\
\(\frac{100}{v_A} - \frac{134}{v_A} = 5\).
Simplifying leads to:
\(\frac{66}{v_A} = 5\) or \( v_A = \frac{66}{5} = 13.2\) m/s.
Finally, to find the time A takes to run 200 meters:
\( t = \frac{200}{v_A} = \frac{200}{13.2}\).
This simplifies to approximately 15.15 seconds per 100 meters, so for 200 meters:
\(2 \times 15.15 = 30.3\) seconds.
Thus, rounding to the nearest whole number, A takes 30 seconds to run 200 meters.
Find the missing code:
L1#1O2~2, J2#2Q3~3, _______, F4#4U5~5, D5#5W6~6