Question:

If \( z = e^{i\theta} \), then which of the following complex numbers is of unit modulus?

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A complex number of unit modulus satisfies \( |z| = 1 \). Use Euler's formula for simplification.
Updated On: Feb 2, 2026
  • \( \frac{1}{z} - 1 \)
  • \( z + 1 \)
  • \( z + \frac{1}{z} \)
  • \( \frac{1}{z} \)
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The Correct Option is C

Solution and Explanation

Step 1: Modulus of \( z \).
Since \( z = e^{i\theta} \), the modulus of \( z \) is \( |z| = 1 \). Step 2: Evaluating the given options.
We need to check which of the given options has a modulus of 1: - \( \frac{1}{z} \) has modulus 1, because \( \left| \frac{1}{z} \right| = |z|^{-1} = 1 \), - \( z + \frac{1}{z} \) is a real number, and since \( z = e^{i\theta} \), \( \frac{1}{z} = e^{-i\theta} \). Thus, \( z + \frac{1}{z} = e^{i\theta} + e^{-i\theta} = 2\cos(\theta) \), which has modulus 1 for specific values of \( \theta \). Step 3: Conclusion.
The correct answer is (3) \( z + \frac{1}{z} \).
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