Question:

If y=xx2 y = x - x^2 , then the rate of change of y2 y^2 with respect to x2 x^2 at x=2 x = 2 is: 

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To find the rate of change of one function with respect to another, use the chain rule and express derivatives in terms of the desired variable.
Updated On: Mar 25, 2025
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The Correct Option is C

Solution and Explanation

Step 1: Expressing y2 y^2
Given y=xx2 y = x - x^2 , we square both sides: y2=(xx2)2. y^2 = (x - x^2)^2. Step 2: Differentiating Both Sides
Differentiating both sides with respect to x x : ddx(y2)=2ydydx. \frac{d}{dx} (y^2) = 2y \cdot \frac{dy}{dx}. Now, differentiating y=xx2 y = x - x^2 : dydx=12x. \frac{dy}{dx} = 1 - 2x. Step 3: Finding the Rate of Change of y2 y^2 with Respect to x2 x^2
We need to find d(y2)dx2 \frac{d(y^2)}{dx^2} , which is: d(y2)dx2=ddx(y2)ddx(x2). \frac{d(y^2)}{dx^2} = \frac{\frac{d}{dx} (y^2)}{\frac{d}{dx} (x^2)}. Since ddx(x2)=2x \frac{d}{dx} (x^2) = 2x , we substitute: d(y2)dx2=2y(12x)2x. \frac{d(y^2)}{dx^2} = \frac{2y (1 - 2x)}{2x}. Step 4: Evaluating at x=2 x = 2
First, find y y at x=2 x = 2 : y=222=24=2. y = 2 - 2^2 = 2 - 4 = -2. Substituting x=2 x = 2 and y=2 y = -2 : d(y2)dx2=2(2)(14)2(2)=2(2)(3)4=124=3. \frac{d(y^2)}{dx^2} = \frac{2(-2) (1 - 4)}{2(2)} = \frac{2(-2)(-3)}{4} = \frac{12}{4} = 3. Final Answer: 3 \boxed{3} .
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