We start with the differential equation:
dy/dx = xy + φ(y/x)
Let's make a substitution by setting y = vx:
Then, we find the derivative dx/dy:
dx/dy = v + x * (dv/dy)
Substituting this into the original equation, we have:
v + x * (dv/dy) = v + φ(v)
Now, the equation becomes:
x * (dx/dv) = φ(v) / φ'(v)
Integrating both sides, we get:
ln(x) = ln(φ(v)) + ln(k)
Solving this, we find:
kφ(v) = x
The correct answer is option (A): \(\frac{y^2}{x^2}\)
Let \( f : \mathbb{R} \to \mathbb{R} \) be a twice differentiable function such that \( f(x + y) = f(x) f(y) \) for all \( x, y \in \mathbb{R} \). If \( f'(0) = 4a \) and \( f \) satisfies \( f''(x) - 3a f'(x) - f(x) = 0 \), where \( a > 0 \), then the area of the region R = {(x, y) | 0 \(\leq\) y \(\leq\) f(ax), 0 \(\leq\) x \(\leq\) 2\ is :
A differential equation is an equation that contains one or more functions with its derivatives. The derivatives of the function define the rate of change of a function at a point. It is mainly used in fields such as physics, engineering, biology and so on.
The first-order differential equation has a degree equal to 1. All the linear equations in the form of derivatives are in the first order. It has only the first derivative such as dy/dx, where x and y are the two variables and is represented as: dy/dx = f(x, y) = y’
The equation which includes second-order derivative is the second-order differential equation. It is represented as; d/dx(dy/dx) = d2y/dx2 = f”(x) = y”.
Differential equations can be divided into several types namely