Question:

If $y =\log_{e}x \left(x-2\right)^{2}$ for $ x \ne0 , 2 $ then $y' \left(3\right) = $

Updated On: Jul 6, 2022
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The Correct Option is B

Solution and Explanation

$y =\log_{e}x \left(x-2\right)^{2} = \frac{\log\left(x-2\right)^{2}}{\log e^{x}} $ $= \frac{2\log\left(x-2\right)}{x \log e} = \frac{2\log\left(x-2\right)}{x}$ $ \therefore \frac{dy}{dx} = 2 . \frac{x. \frac{1}{x-2} - \log\left(x-2\right)1}{x^{2}} $ $\therefore y'\left(3\right) = \frac{2}{9} \left(\frac{3}{1} - \log1\right) = \frac{2}{4} \left(3\right) = \frac{2}{3} $
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