Question:
If \(y=\sin^{-1}\frac{1}{2}(\sqrt{1+x}+\sqrt{1-x})\) then y' =
If \(y=\sin^{-1}\frac{1}{2}(\sqrt{1+x}+\sqrt{1-x})\) then y' =
Updated On: Sep 15, 2024
- \(\frac{1}{2\sqrt{1-x^2}}\)
- \(\frac{-1}{2\sqrt{1-x^2}}\)
- \(\frac{1}{2\sqrt{1+x^2}}\)
- \(\frac{-1}{2\sqrt{1+x^2}}\)
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The Correct Option is B
Solution and Explanation
The correct option is B) : \(\frac{-1}{2\sqrt{1-x^2}}\).
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