Question

If \(y=\sin^{-1}\frac{1}{2}(\sqrt{1+x}+\sqrt{1-x})\) then y' =

• A. \(\frac{1}{2\sqrt{1-x^2}}\)
• B. \(\frac{-1}{2\sqrt{1-x^2}}\)
• C. \(\frac{1}{2\sqrt{1+x^2}}\)
• D. \(\frac{-1}{2\sqrt{1+x^2}}\)

Answer 1

The Correct Option is B

The correct option is B) : \(\frac{-1}{2\sqrt{1-x^2}}\).