We are told:
\[
x \mid (2x + 12) \Rightarrow \frac{2x + 12}{x} = \text{integer}
\Rightarrow 2 + \frac{12}{x} \in \mathbb{Z}
\Rightarrow \frac{12}{x} \in \mathbb{Z}
\]
So $x$ must divide 12. Positive divisors of 12:
\[
x \in \{1, 2, 3, 4, 6, 12\}
\Rightarrow \boxed{6} \text{ values}
\]