Given: The polynomial is:f(x) = x³ - 4x² + ax + 8
and it is given that (x - 2)
is a factor of the polynomial.
Step 1: Recall the Factor Theorem
Factor Theorem states that if (x - c)
is a factor of a polynomial f(x)
, then f(c) = 0
.
Step 2: Apply the Factor Theorem
Since (x - 2)
is a factor, we substitute x = 2
into the polynomial and set the result equal to zero:
f(2) = (2)³ - 4(2)² + a(2) + 8
= 8 - 16 + 2a + 8
Step 3: Simplify the expression
Combine like terms: f(2) = (8 - 16 + 8) + 2a = 0 + 2a
Step 4: Solve for 'a'
2a = 0
⇒ a = 0
Final Answer: a = 0
Hence, the correct option is Option (1): 0
If \( \vec{u}, \vec{v}, \vec{w} \) are non-coplanar vectors and \( p, q \) are real numbers, then the equality:
\[ [3\vec{u} \quad p\vec{v} \quad p\vec{w}] - [p\vec{v} \quad \vec{w} \quad q\vec{u}] - [2\vec{w} \quad q\vec{v} \quad q\vec{u}] = 0 \]
holds for: