If x \(\begin{bmatrix}2\\3\end{bmatrix}\)+y \(\begin{bmatrix}-1\\1\end{bmatrix}\)=\(\begin{bmatrix}10\\5\end{bmatrix}\),find values of x and y.
x \(\begin{bmatrix}2\\3\end{bmatrix}\)+y \(\begin{bmatrix}-1\\1\end{bmatrix}\)=\(\begin{bmatrix}10\\5\end{bmatrix}\)
\(\Rightarrow \begin{bmatrix}2x\\3x\end{bmatrix}+\begin{bmatrix}-y\\y\end{bmatrix}\)=\(\begin{bmatrix}10\\5\end{bmatrix}\)
\(\Rightarrow \begin{bmatrix}2x-y\\3x+y\end{bmatrix}\)=\(\begin{bmatrix}10\\5\end{bmatrix}\)
Comparing the corresponding elements of these two matrices, we get:
2x − y = 10 and 3x + y = 5
Adding these two equations, we have:
5x = 15
\(\Rightarrow\) x = 3
Now, 3x + y = 5
\(\Rightarrow\) y = 5 − 3x
\(\Rightarrow\) y = 5 − 9 = −4
∴x = 3 and y = −4
If \[ A = \begin{bmatrix} 1 & 2 & 0 \\ -2 & -1 & -2 \\ 0 & -1 & 1 \end{bmatrix} \] then find \( A^{-1} \). Hence, solve the system of linear equations: \[ x - 2y = 10, \] \[ 2x - y - z = 8, \] \[ -2y + z = 7. \]
Complete and balance the following chemical equations: (a) \[ 2MnO_4^-(aq) + 10I^-(aq) + 16H^+(aq) \rightarrow \] (b) \[ Cr_2O_7^{2-}(aq) + 6Fe^{2+}(aq) + 14H^+(aq) \rightarrow \]
Balance Sheet of Chandan, Deepak and Elvish as at 31st March, 2024
Liabilities | Amount (₹) | Assets | Amount (₹) |
---|---|---|---|
Capitals: | Fixed Assets | 27,00,000 | |
Chandan | 7,00,000 | Stock | 3,00,000 |
Deepak | 5,00,000 | Debtors | 2,00,000 |
Elvish | 3,00,000 | Cash | 1,00,000 |
General Reserve | 4,50,000 | ||
Creditors | 13,50,000 | ||
Total | 33,00,000 | Total | 33,00,000 |