To find the product of the roots of the quadratic equation \(x^2 - 3x + 2 = 0\),
we use Viète's formulas, which relate the coefficients of a polynomial to sums and products of its roots.
For a quadratic equation of the form \(ax^2 + bx + c = 0\),
the product of the roots (\(P\)) is given by:
\[P = \frac{c}{a}\]
Here, \(a = 1\), \(b = -3\), and \(c = 2\).
Substitute these values into the formula:
\[P = \frac{2}{1} = 2\]
Thus, the product of the roots is 2.
For any natural number $k$, let $a_k = 3^k$. The smallest natural number $m$ for which \[ (a_1)^1 \times (a_2)^2 \times \dots \times (a_{20})^{20} \;<\; a_{21} \times a_{22} \times \dots \times a_{20+m} \] is: