In linear simple harmonic motion, the acceleration and velocity of the particle are related to each other.
The acceleration is maximum when the particle is at the extreme positions (maximum displacement) of the oscillation. At these points, the velocity is momentarily zero, as the particle changes direction.
when the acceleration is zero, the particle is at the equilibrium position (midpoint) of the oscillation, and at this point, the velocity is also zero.
Therefore, when 'a' is zero, 'v' is zero.
In linear simple harmonic motion (SHM):
Acceleration a is maximum at the extremes of displacement (maximum amplitude), where the particle changes direction.
Velocity v is zero at these extremes because the particle momentarily stops before changing direction.
Acceleration is zero at the equilibrium position (midpoint) of the oscillation, where the restoring force is zero.
Velocity is also zero at the equilibrium position because the particle momentarily stops before reversing its direction of motion.
Therefore, the statement "when 'a' is zero, 'v' is zero" accurately describes the relationship between acceleration and velocity in linear SHM.
So, the correct option is (C): When 'a' is zero, 'v' is zero.
The center of a disk of radius $ r $ and mass $ m $ is attached to a spring of spring constant $ k $, inside a ring of radius $ R>r $ as shown in the figure. The other end of the spring is attached on the periphery of the ring. Both the ring and the disk are in the same vertical plane. The disk can only roll along the inside periphery of the ring, without slipping. The spring can only be stretched or compressed along the periphery of the ring, following Hooke’s law. In equilibrium, the disk is at the bottom of the ring. Assuming small displacement of the disc, the time period of oscillation of center of mass of the disk is written as $ T = \frac{2\pi}{\omega} $. The correct expression for $ \omega $ is ( $ g $ is the acceleration due to gravity):