Question:

If unit vectors $\hat{A}$ and $\hat{B}$ are inclined at an angle $\theta$, then $\left|\hat{A}-\hat{B}\right|$ is

Updated On: Jul 6, 2022
  • $2\,sin \frac{\theta}{2}$
  • $2\,cos \frac{\theta}{2}$
  • $2\,tan \frac{\theta}{2}$
  • $tan\theta$
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The Correct Option is A

Solution and Explanation

$\left|\hat{A}-\hat{B}\right|^{2}=\left|\hat{A}\right|^{2}+\left|\hat{B}\right|^{2}-2\,\hat{A}\cdot\hat{B}$ $=2-2cos\theta=2\left(1-cos\theta\right)\,\left(\because \left|\hat{A}\right|=\left|\hat{B}\right|=1\right)$ $=2\left(sin^{2} \frac{\theta}{2}\right)$ $=4\,sin^{2} \frac{\theta}{2}$ or $\left|\hat{A}-\hat{B}\right|=2\,sin \frac{\theta}{2}$
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Concepts Used:

Motion in a Plane

It is a vector quantity. A vector quantity is a quantity having both magnitude and direction. Speed is a scalar quantity and it is a quantity having a magnitude only. Motion in a plane is also known as motion in two dimensions. 

Equations of Plane Motion

The equations of motion in a straight line are:

v=u+at

s=ut+½ at2

v2-u2=2as

Where,

  • v = final velocity of the particle
  • u = initial velocity of the particle
  • s = displacement of the particle
  • a = acceleration of the particle
  • t = the time interval in which the particle is in consideration