Question:

If \(u=\sin^{-1}(\frac{2x}{1+x^2})\) and \(v=\tan^{-1}(\frac{2x}{1-x^2})\) then \(\frac{du}{dv}\) is

Updated On: Apr 17, 2024
  • \(\frac{1-x^2}{1+x^2}\)
  • \(\frac{1}{2}\)
  • 1
  • 2
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The Correct Option is C

Solution and Explanation

The correct answer is (C) : 1.
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