Question

If two dice are tossed together, then the probability of getting the sum of numbers on both the dice as 10 is:

• A. $\dfrac{1}{12}$
• B. $\dfrac{1}{6}$
• C. $\dfrac{1}{4}$
• D. $\dfrac{1}{8}$

Hint:

When rolling two dice, always count pairs that give the required sum. There are 36 total outcomes.

Answer 1

The Correct Option is A

Step 1: List total possible outcomes.
When two dice are rolled, total outcomes = 6 × 6 = 36.

Step 2: Find outcomes where sum = 10.
Possible pairs: (4,6), (5,5), (6,4). So, number of favorable outcomes = 3.

Step 3: Apply probability formula.
\[ P(E) = \dfrac{\text{Favorable outcomes}}{\text{Total outcomes}} = \dfrac{3}{36} = \dfrac{1}{12} \]
Step 4: Conclusion.
Therefore, the required probability is $\dfrac{1}{12}$.