Step 1: Using the condition for coplanarity.
Three vectors are coplanar if and only if their scalar triple product is zero. The scalar triple product of vectors \( \mathbf{a}, \mathbf{b}, \mathbf{c} \) is given by:
\[
\mathbf{a} \cdot (\mathbf{b} \times \mathbf{c}) = 0
\]
Step 2: Substituting the vectors.
Let the vectors be:
\[
\mathbf{a} = (1, 1, 1), \quad \mathbf{b} = (1, -1, 1), \quad \mathbf{c} = (2, 3, m)
\]
We compute the cross product \( \mathbf{b} \times \mathbf{c} \) and then take the dot product with \( \mathbf{a} \). After solving, we find that \( m = 2 \).
Step 3: Conclusion.
Thus, \( m = 2 \), which makes option (C) the correct answer.