If the standard deviation of first n natural numbers is 2, then the value of n is
Concept:
The standard deviation (SD) is a measure of the dispersion or spread of a set of values. For the first n natural numbers, the formula for standard deviation is derived from the variance formula for an arithmetic series.
The standard deviation of the first n natural numbers (1, 2, 3, ..., n) is given by:
SD =
\(\sqrt{\frac{n^2 - 1}{12}}\)
Given: Standard deviation = 2
So we set up the equation:
\(2 = \sqrt{\frac{n^2 - 1}{12}}\)
Step-by-step Calculation:
1. Square both sides:
\(4 = \frac{n^2 - 1}{12}\)
2. Multiply both sides by 12:
\(48 = n^2 - 1\)
3. Add 1 to both sides:
\(n^2 = 49\)
4. Take square root:
\(n = \sqrt{49} = 7\)
Conclusion:
The value of n for which the standard deviation of the first n natural numbers is 2 is 7.
Therefore, the correct option is: (B) 7.
Variance of the following discrete frequency distribution is:
\[ \begin{array}{|c|c|c|c|c|c|} \hline \text{Class Interval} & 0-2 & 2-4 & 4-6 & 6-8 & 8-10 \\ \hline \text{Frequency (}f_i\text{)} & 2 & 3 & 5 & 3 & 2 \\ \hline \end{array} \]