Question:

If the roots of the equation z2 - i = 0 are α and β, then | Arg β - Arg α | =

Updated On: May 4, 2025
  • π/2

  • π

  • π/4

Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is C

Solution and Explanation

To solve the problem, we need to find the difference in arguments (angles) of the roots of the complex equation \( z^2 - i = 0 \).

1. Solve the Equation:
We are given the equation:
\( z^2 = i \)
To find \( z \), we take square roots of \( i \):
In polar form, \( i = \cos\left(\frac{\pi}{2}\right) + i\sin\left(\frac{\pi}{2}\right) \), so:
\( z = \sqrt{i} = \sqrt{r} \left[ \cos\left(\frac{\theta}{2}\right) + i\sin\left(\frac{\theta}{2}\right) \right] \)
where \( r = 1 \), \( \theta = \frac{\pi}{2} \).
So the roots are:
\( z_1 = \cos\left(\frac{\pi}{4}\right) + i\sin\left(\frac{\pi}{4}\right) = \frac{1}{\sqrt{2}} + i\frac{1}{\sqrt{2}} \)
\( z_2 = \cos\left(\frac{5\pi}{4}\right) + i\sin\left(\frac{5\pi}{4}\right) = -\frac{1}{\sqrt{2}} - i\frac{1}{\sqrt{2}} \)

2. Find Arguments of Roots:
\( \arg(\alpha) = \arg(z_1) = \frac{\pi}{4} \)
\( \arg(\beta) = \arg(z_2) = \frac{5\pi}{4} \)

3. Calculate the Difference:
\( |\arg(\beta) - \arg(\alpha)| = \left| \frac{5\pi}{4} - \frac{\pi}{4} \right| = \pi \)

Final Answer:
The value of \( |\arg(\beta) - \arg(\alpha)| \) is \( \boxed{\pi} \).

Was this answer helpful?
18
43

Top Questions on Complex numbers

View More Questions

Concepts Used:

Complex Number

A Complex Number is written in the form

a + ib

where,

  • “a” is a real number
  • “b” is an imaginary number

The Complex Number consists of a symbol “i” which satisfies the condition i^2 = −1. Complex Numbers are mentioned as the extension of one-dimensional number lines. In a complex plane, a Complex Number indicated as a + bi is usually represented in the form of the point (a, b). We have to pay attention that a Complex Number with absolutely no real part, such as – i, -5i, etc, is called purely imaginary. Also, a Complex Number with perfectly no imaginary part is known as a real number.