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if the roots of the equation 3x 2 5x q 0 are equal
Question:
If the roots of the equation \(3x^2 + 5x - q = 0\) are equal, then the value of \(q\) will be
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For equal roots, always apply the discriminant condition \(D = 0\).
UP Board X - 2024
UP Board X
Updated On:
Nov 6, 2025
$-\dfrac{25}{12}$
$-\dfrac{25}{9}$
$\dfrac{9}{25}$
$-\dfrac{12}{25}$
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The Correct Option is
B
Solution and Explanation
Step 1: Recall the condition for equal roots.
For a quadratic \(ax^2 + bx + c = 0\), roots are equal when \[ D = b^2 - 4ac = 0 \]
Step 2: Substitute values.
Here, \(a = 3, b = 5, c = -q\). \[ b^2 - 4ac = 0 \implies 25 - 4(3)(-q) = 0 \]
Step 3: Simplify.
\[ 25 + 12q = 0 \Rightarrow q = -\dfrac{25}{12} \]
Step 4: Verify given options.
Correct answer matches option (A) $-\dfrac{25}{12}$. (Note: If the printed options differ, the logic confirms this value.)
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